x^2+14(x)+47=0

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Solution for x^2+14(x)+47=0 equation:


Simplifying
x2 + 14(x) + 47 = 0

Reorder the terms:
47 + 14x + x2 = 0

Solving
47 + 14x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-47' to each side of the equation.
47 + 14x + -47 + x2 = 0 + -47

Reorder the terms:
47 + -47 + 14x + x2 = 0 + -47

Combine like terms: 47 + -47 = 0
0 + 14x + x2 = 0 + -47
14x + x2 = 0 + -47

Combine like terms: 0 + -47 = -47
14x + x2 = -47

The x term is 14x.  Take half its coefficient (7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
14x + 49 + x2 = -47 + 49

Reorder the terms:
49 + 14x + x2 = -47 + 49

Combine like terms: -47 + 49 = 2
49 + 14x + x2 = 2

Factor a perfect square on the left side:
(x + 7)(x + 7) = 2

Calculate the square root of the right side: 1.414213562

Break this problem into two subproblems by setting 
(x + 7) equal to 1.414213562 and -1.414213562.

Subproblem 1

x + 7 = 1.414213562 Simplifying x + 7 = 1.414213562 Reorder the terms: 7 + x = 1.414213562 Solving 7 + x = 1.414213562 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + x = 1.414213562 + -7 Combine like terms: 7 + -7 = 0 0 + x = 1.414213562 + -7 x = 1.414213562 + -7 Combine like terms: 1.414213562 + -7 = -5.585786438 x = -5.585786438 Simplifying x = -5.585786438

Subproblem 2

x + 7 = -1.414213562 Simplifying x + 7 = -1.414213562 Reorder the terms: 7 + x = -1.414213562 Solving 7 + x = -1.414213562 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + x = -1.414213562 + -7 Combine like terms: 7 + -7 = 0 0 + x = -1.414213562 + -7 x = -1.414213562 + -7 Combine like terms: -1.414213562 + -7 = -8.414213562 x = -8.414213562 Simplifying x = -8.414213562

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-5.585786438, -8.414213562}

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